A very simple screener to find quickly the values breaking their 3 last months highest point.
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// Find max value in last 3 months maxValue = highest[90](high)[1] // Volume condition avgVol = average[20](volume) sum = 0 for i=0 to 20 if (volume[i] < avgVol*10) then sum = sum + volume[i] else sum = sum + avgVol endif next avgVol = sum / 21 // Screener SCREENER[maxvalue < close and open < maxvalue and avgVol > 1000] |
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Re bonjour Vivien,
Il me smeble que 3 mois, c’est 60 séances.
Cordialement,
thanks …and It can be used on a monthly and weekly basis by changing just the duration in maxValue = highest[21/5](high)[1]