: Forum Vela de 1 hora y dentro las 5 de 15 minutos

07/25/2024 at 3:04 PM #235785

Iván

Hola,
te refieres a algo como esto?

if barindex>1 then
if openhour<>openhour[1] then
close1h=close[1]
open1h=open[bar+1]
high1h=highest[bar+1](high)[1]
low1h=lowest[bar+1](low)[1]
drawrectangle(barindex[bar[1]+1],close1h,barindex[1],open1h)coloured("blue")
drawsegment(barindex[2],high1h,barindex[2],low1h)coloured("blue")
bar=0
else
bar=1+bar
endif
endif

return

if barindex>1 then

if openhour<>openhour[1] then

close1h=close[1]

open1h=open[bar+1]

high1h=highest[bar+1](high)[1]

low1h=lowest[bar+1](low)[1]

drawrectangle(barindex[bar[1]+1],close1h,barindex[1],open1h)coloured("blue")

drawsegment(barindex[2],high1h,barindex[2],low1h)coloured("blue")

bar=0

else

bar=1+bar

endif

return

Iván

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