: Forum Programmer une résistance

02/21/2025 at 3:24 PM #244161

Iván

Hola, je peux considérer par exemple un prix qui nous permet de pivoter haut est très proche et qui en outre se compose des conditions mentionnées (fermer> sma et fermer

prd=20
lmax=highest[prd](high)
sma=average[200](close)

ph1=high<high[prd]
ph2=highest[prd](high)<high[prd]
ph3=high[prd]>highest[prd](high)[prd+1]

if ph1 and ph2 and ph3 then
prevph=ph
ph=high[prd]
endif

ll1=low>low[prd]
ll2=lowest[prd](low)>low[prd]
ll3=low[prd]<lowest[prd](low)[prd+1]

if ll1 and ll2 and ll3 then
pl=low[prd]
endif

diff=(ph/prevph-1)*100

c1=close<lmax and high<ph
c2=close>sma
c3=abs(diff)<3
c4=pl>sma

inrange=c1 and c2 and c3 and c4

screener[inrange](diff as “%diff”)

prd=20

lmax=highest[prd](high)

sma=average[200](close)

ph1=high<high[prd]

ph2=highest[prd](high)<high[prd]

ph3=high[prd]>highest[prd](high)[prd+1]

if ph1 and ph2 and ph3 then

prevph=ph

ph=high[prd]

endif

ll1=low>low[prd]

ll2=lowest[prd](low)>low[prd]

ll3=low[prd]<lowest[prd](low)[prd+1]

if ll1 and ll2 and ll3 then

pl=low[prd]

endif

diff=(ph/prevph-1)*100

c1=close<lmax and high<ph

c2=close>sma

c3=abs(diff)<3

c4=pl>sma

inrange=c1 and c2 and c3 and c4

screener[inrange](diff as “%diff”)

Iván

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