12 combination indicator (trying to create)

• 02/21/2020 at 5:30 PM #120171
  BjornH

  Hi!

  Very new to this, but I am trying to write my very own combination indicator, without much success.

  What I want to create is a indicator line that goes from it lowest value “0” (if none of the requirements are met) to the highest “12”(if all requirements are met)

  My guess is that I need to first create a variable called something like “CountingVariable” … and then, as conditions are met, it will add a +1 to this variable …

  The conditions are:

  if

  • HVO[100] > 20(close) then add +1 point
  • RSI[7](close) > 80 … 3-16 days ago then add +1 point
  • Upper BollingerBand[20, 2stdev] pointing upwards then add +1 point
  • Todays date is between the 24th this month and the 3rd the coming month, then add +1 point
  • Close > average[200] then add +1 point
  • CCI[6] crosses over -100 then add+1 point
  • RSI[2](close) 3 days ago < 60, then add +1 point
  • RSI[2](close) fallen for 3 days, then add +1 point
  • %D[5](close) < 10 then add +1 point
  • RSI[2](close) < 20 then add +1 point
  • RSI[2](close) < 10 then add +1 point

  But how do I create the function that adds 1 point to the indicator line for every requirement that is met … ?

  

  BjornH

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  02/21/2020 at 5:55 PM #120172
  Vonasi

  Like this:

  count = 0 if RSI[2] < 20 then count = count + 1 endif if RSI[2] < 10 then count = count + 1 endif //.....and repeat another 10 times. return count

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  count = 0   if RSI[2] < 20 then count = count + 1 endif   if RSI[2] < 10 then count = count + 1 endif   //.....and repeat another 10 times.   return count

   

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  Vonasi

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  02/21/2020 at 6:00 PM #120174
  Vonasi

  Personally I prefer to present the result as a % so would do it like this so that you can add or remove conditions and the calculations still works.

  count = 0 tests = 0 if RSI[2] < 20 then count = count + 1 endif tests = tests + 1 if RSI[2] < 10 then count = count + 1 endif tests = tests + 1 //.....and repeat however many times you like. result = (count/tests)*100 return result

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  count = 0 tests = 0   if RSI[2] < 20 then count = count + 1 endif tests = tests + 1   if RSI[2] < 10 then count = count + 1 endif tests = tests + 1   //.....and repeat however many times you like.   result = (count/tests)*100   return result

   

  

  Vonasi

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  02/21/2020 at 6:27 PM #120179
  BjornH

  Wow, thank you very much!

  Is it to much to ask for if you could help me with the function for the date conditions ?

  I´m trying to find something in the help section for the limitation between the 24th this month and the 3rd the coming month … But as I can see it I can only return the current date?

  So I guess I need to make the function that brings up todays date and then look if this date is between the 24th and the 31st this month, or between the 1st and the 3rd the upcoming month … Will an error occur because there are some months with only 30 days etc … ?

  And when I want to check if RSI[2] was < 60 3 days ago ….  and fallen for 3 days … do I need to write an IF function for this as well ?

  • Todays date is between the 24th this month and the 3rd the coming month, then add +1 point
  • RSI[2](close) 3 days ago < 60, then add +1 point
  • RSI[2](close) fallen for 3 days, then add +1 point

  

  BjornH

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  02/21/2020 at 6:30 PM #120181
  BjornH

  Like this condition

   

  RSI[7](close) > 80 3-16 days ago …..

   

  this is giving me a headache =)

  

  BjornH

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  02/21/2020 at 6:38 PM #120185
  BjornH

  count = 0 if date =>24 and <=31 then count = 0 + 1 endif if date =>1 and <=3 then count = 0 + 1 endif

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  count = 0   if date =>24 and <=31 then count = 0 + 1 endif   if date =>1 and <=3 then count = 0 + 1 endif

  something like this … ?

  

  BjornH

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  02/21/2020 at 6:43 PM #120188
  Vonasi

  OPENDAY returns the day of the month that a candle opens on so:

  if openday >=24 or openday <= 3 then count = count + 1 endif tests = tests + 1

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  if openday >=24 or openday <= 3 then count = count + 1 endif tests = tests + 1

  The number of days in the month makes no difference.

  RSI < 60 three days ago is a little more complicated depending upon what time frame you are using or if you want it to work on all time frames?

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  Vonasi

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  02/21/2020 at 6:58 PM #120189
  BjornH

  It is for daily charts, yes. Only Daily  …

   

  Thank you very much

  

  BjornH

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  02/21/2020 at 7:08 PM #120190
  Vonasi

  That’s easier then. The current bar is bar 0 so three days ago is bar 3.

  if rsi[2](close[3]) < 60 then

  1	if rsi[2](close[3]) < 60 then

  Falling for 3 days needs a SUMMATION.

  if summation[3](rsi[2](close) < rsi[2](close[1])) = 3 then

  1	if summation[3](rsi[2](close) < rsi[2](close[1])) = 3 then

  This will check the last 3 days including the current one.

   

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  Vonasi

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  02/21/2020 at 7:11 PM #120191
  Vonasi

  BjornH wrote:

  Like this condition

  RSI[7](close) > 80 3-16 days ago …..

  this is giving me a headache =)

  You’ll have to clarify this. Do you mean it was > 80 at any point during the period from 3 days ago to 16 days ago?

  

  Vonasi

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  02/21/2020 at 7:19 PM #120192
  BjornH

  Yes, exactly … price had to print above 80 in the period: 3 to 16 days ago ….

   

  So grateful for your help … reading the help documentation can only take you so far …

  

  BjornH

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  02/21/2020 at 7:25 PM #120193
  Vonasi

  This should do it:

  if summation[14](rsi[7](close[3]) > 80) <> 0 then

  1	if summation[14](rsi[7](close[3]) > 80) <> 0 then

   

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