1st and 2nd etc lowest lows in a data set

• 02/05/2023 at 10:18 PM #209164
  robert123

  Hi All,

  Whilst I understand how to find the lowest low in a data set (bounded oscillator), is it, and if it is possible, how do I find the second or third lowest low?

  TIA

  Robert

  

  robert123

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  02/05/2023 at 11:59 PM #209174
  JS

  Hi @Robert123

  Perhaps not the most elegant way…

   

   

  3 Lows

  DefParam DrawOnLastBarOnly=true For i=0 to 20 $Low[i]=Low[i] Next ArraySort($Low,Ascend) Low1=$Low[0] Low2=$Low[1] Low3=$Low[2] DrawText("Low1=#Low1#",BarIndex,High+30) DrawText("Low2=#Low2#",BarIndex,High+20) DrawText("Low3=#Low3#",BarIndex,High+10) Return

  1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16

  DefParam DrawOnLastBarOnly=true   For i=0 to 20 $Low[i]=Low[i] Next   ArraySort($Low,Ascend) Low1=$Low[0] Low2=$Low[1] Low3=$Low[2]   DrawText("Low1=#Low1#",BarIndex,High+30) DrawText("Low2=#Low2#",BarIndex,High+20) DrawText("Low3=#Low3#",BarIndex,High+10)   Return

  

  JS

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  02/06/2023 at 10:45 AM #209207
  JS

  Hi Robert,

  A small explanation (if necessary)…

  You fill the array $Low with the last 20 “Lows”…

  You sort the array $Low ascending so that the “smallest lows” are at the front…

  After this you can use the obtained values as you wish…

  

  JS

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  02/06/2023 at 10:50 AM #209209
  robert123

  JS,

  Thank you very much works perfectly- after several coffees!

  Again thanks for your help.

  RR

  1 user thanked author for this post.

  JS

  

  robert123

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