3 Lower Lows

• 10/24/2019 at 4:05 PM #111099
  JackD

  Hi,

  I would like to get some code so I can scan for  3 lower lows on the daily chart.

  Would anyone be able to help me with that?

  Cheers

  Jack

  

  JackD

  Participant

  Topics: 6

  Replies: 16

  Been thanked: 0 times
  10/25/2019 at 12:26 AM #111132
  robertogozzi

  There you go:

  x = (summation[2](low < low[1]) = 2) Screener[x]

  1 2	x = (summation[2](low < low[1]) = 2) Screener[x]

   

  

  robertogozzi

  Moderator

  Topics: 69

  Replies: 17415

  Been thanked: 4196 times
  10/25/2019 at 1:03 AM #111135
  JackD

  Great, thank you so much!!

  

  JackD

  Participant

  Topics: 6

  Replies: 16

  Been thanked: 0 times
  10/25/2019 at 7:43 AM #111150
  robertogozzi

  Sorry, but perhaps 3 is better instead of 2.

  2 compares 3 lows, but does not guarantee that the 3rd one is really lower than its previous one, while 3 compares 4 lows thus making sure ALL 3 are lower than their previous ones.

  

  robertogozzi

  Moderator

  Topics: 69

  Replies: 17415

  Been thanked: 4196 times
  10/25/2019 at 11:08 AM #111174
  JackD

  No it’s okay. Cool thank you Roberto for all your help
  I just tried to change it but it’s not working as I am not doing it correctly. I have just started to look at code and have no idea how to write it at all.

  

  JackD

  Participant

  Topics: 6

  Replies: 16

  Been thanked: 0 times
  10/25/2019 at 12:46 PM #111193
  GraHal

  Roberto meant as below …

  x = (summation[3](low < low[1]) = 3) Screener[x]

  1 2	x = (summation[3](low < low[1]) = 3) Screener[x]

   

  

  GraHal

  Participant

  Topics: 215

  Replies: 8919

  Been thanked: 2241 times
  10/25/2019 at 12:48 PM #111195
  JackD

  O thank you.
  Haha I have been trying to write it all arvo.

  

  JackD

  Participant

  Topics: 6

  Replies: 16

  Been thanked: 0 times
• Author
  Posts