Bug fonction drawarrow / Up

• 06/10/2020 at 12:16 PM #135414
  GilInvest

  Bonjour à tous, ProBuilder refuse mes lignes 17 et 36 (DRAWARROWDOWN et DRAWARROWUP, dans les structures conditionnelles portant sur les engulfing, sont soulignées indiquant un bug. Voir PJ). Je n’arrive pas a comprendre. Ca viendrait y pas du fait qu’il y aurait conflit avec 2 autres instructions incluant ces mêmes fonctions ? Par avance merci pour vos lumières. PS : dans la fenêtre de dialogue il y a “erreur de synthaxe ligne 17, caractere 88. Une des expressions suivantes serait plus appropriées que DRAWARROWdown” : “\n” . Je ne vois pas du tout a quoi correspondarit ce ” \n ”

  Code indicateur de break et engulfing

  atr10=averagetruerange[10] once Breakupsignal = 0 once Breakdownsignal = 0 once engulfing = 0 If close>exponentialaverage[100] and open[0]<ExponentialAverage[7] and open[0]<ExponentialAverage[20] and high[0]>ExponentialAverage[7] and high[0]>ExponentialAverage[20] and close[0]>open[0] then DRAWARROWUP(barindex[0],low-atr10/2) coloured(0,200,0) Breakupsignal =1 else Breakupsignal =0 endif If close>exponentialaverage[100] and close<open and close<low[1] and open>high[1] then DRAWARROWdown(barindex[0],low-atr10/2) coloured(255,165,0) engulfing=1 else engulfing=0 endif If close<exponentialaverage[100] and open[0]>ExponentialAverage[7] and open[0]>ExponentialAverage[20] and high[0]<ExponentialAverage[7] and high[0]<ExponentialAverage[20] and close[0]<open[0] then DRAWARROWdown (barindex[0],low-atr10/2) coloured(200,0,0) Breakdownsignal =-1 else Breakdownsignal =0 endif If close<exponentialaverage[100] and close>open and close>low[1] and open<high[1] then DRAWARROWUP(barindex[0],low-atr10/2) coloured(255,165,0) engulfing =-1 else engulfing =0 endif return Breakupsignal coloured(120,210,120) style(histogram), Breakdownsignal coloured(210,120,120) style(histogram), engulfing coloured(255,165,0) style(histogram), 0 as "0"

  1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45

  atr10=averagetruerange[10] once Breakupsignal = 0 once Breakdownsignal = 0 once engulfing = 0   If close>exponentialaverage[100] and open[0]<ExponentialAverage[7] and open[0]<ExponentialAverage[20] and high[0]>ExponentialAverage[7] and high[0]>ExponentialAverage[20] and close[0]>open[0] then DRAWARROWUP(barindex[0],low-atr10/2) coloured(0,200,0) Breakupsignal =1   else   Breakupsignal =0   endif   If close>exponentialaverage[100] and close<open and close<low[1] and open>high[1] then DRAWARROWdown(barindex[0],low-atr10/2) coloured(255,165,0) engulfing=1   else   engulfing=0   endif   If close<exponentialaverage[100] and open[0]>ExponentialAverage[7] and open[0]>ExponentialAverage[20] and high[0]<ExponentialAverage[7] and high[0]<ExponentialAverage[20] and close[0]<open[0] then DRAWARROWdown (barindex[0],low-atr10/2) coloured(200,0,0) Breakdownsignal =-1   else   Breakdownsignal =0   endif   If close<exponentialaverage[100] and close>open and close>low[1] and open<high[1] then DRAWARROWUP(barindex[0],low-atr10/2) coloured(255,165,0) engulfing =-1   else   engulfing =0   endif   return Breakupsignal coloured(120,210,120) style(histogram), Breakdownsignal coloured(210,120,120) style(histogram), engulfing coloured(255,165,0) style(histogram), 0 as "0"

   

  

  GilInvest

  Participant

  Topics: 14

  Replies: 35

  Been thanked: 2 times
  06/10/2020 at 12:22 PM #135416
  robertogozzi

  APRÈS le mot-clé “THEN” il ne doit rien y avoir, vous devrez commencer une nouvelle ligne.

  1 user thanked author for this post.

  GilInvest

  

  robertogozzi

  Moderator

  Topics: 69

  Replies: 17153

  Been thanked: 4040 times
  06/10/2020 at 12:39 PM #135420
  Nicolas

  Voir formation sur les structures conditionnelles : https://www.prorealcode.com/chapter/tests-simples-avec-if-endif/

  1 user thanked author for this post.

  GilInvest

  

  Nicolas

  Keymaster

  Topics: 81

  Replies: 20863

  Been thanked: 4773 times
  06/10/2020 at 1:04 PM #135426
  GilInvest

  Humm, merci. J’ai justement fait cette leçon ce week end et ai voulu appliquer. Je vais regarder à nouveau.

  

  GilInvest

  Participant

  Topics: 14

  Replies: 35

  Been thanked: 2 times
  06/10/2020 at 1:25 PM #135433
  GilInvest

  Well, j’ai regardé à nouveau; ai comparé / revu mon code > de mon point de vue, j’ai respecté toutes les conditions expliquées.  Je n’ai pas mis de structures imbriquée. J’ai mis les blocs conditionnels, les uns après les autres incluant chacun les instructions IF / THEN / ENDIF. Bref, je ne vois pas ou se situe le bug. Si tu peux m’éclairer, je suis preneur. Merci

  

  GilInvest

  Participant

  Topics: 14

  Replies: 35

  Been thanked: 2 times
  06/10/2020 at 2:08 PM #135436
  robertogozzi

  IF Condition THEN xyz . ENDIF

  1 2 3 4

  IF Condition THEN   xyz   . ENDIF

  pas

  IF Condition THEN xyz . . ENDIF

  1 2 3 4

  IF Condition THEN xyz . . ENDIF

   

  

  robertogozzi

  Moderator

  Topics: 69

  Replies: 17153

  Been thanked: 4040 times
  06/10/2020 at 3:02 PM #135448
  GilInvest

  Wow thanks Extremely subtle. I bet I could find out this detail. Thank you so much.

  Ouah merci. Extrêmement subtil. Je parie que je pourrais découvrir ce détail. Merci beaucoup.

  

  GilInvest

  Participant

  Topics: 14

  Replies: 35

  Been thanked: 2 times
• Author
  Posts