Contract size calculation issue

• 08/24/2019 at 8:49 AM #105424
  BC

  Original Code

  PositionSizeLong = MIN(10,MAX(0.5,abs(round((LongMaxRisk/(Close*(MaxSLPrecentageLong/100))/PointValue)*pipsize))))

  1	PositionSizeLong = MIN(10,MAX(0.5,abs(round((LongMaxRisk/(Close*(MaxSLPrecentageLong/100))/PointValue)*pipsize))))

  Hi PRT Master

   

  Above code give the contract size result as 0.5, 1, 2, 3, 4……10.

  What command should use to make it 0.5, 1, 1.5, 2.0, 2.5……..10?

   

  Thanks.

   

  

  BC

  Participant

  Topics: 24

  Replies: 170

  Been thanked: 34 times
  08/24/2019 at 9:28 AM #105425
  robertogozzi

  I have not tested it for lack of missing values, but this is your line as I modified it, plus another line to avoid 0.1, 02, …

  PositionSizeLong = abs((round(((LongMaxRisk/(Close*(MaxSLPrecentageLong/100))*10)/PointValue)/10)*pipsize) PositionSizeLong = PositionSizeLong - (PositionSizeLong MOD 0.5)

  1 2	PositionSizeLong = abs((round(((LongMaxRisk/(Close*(MaxSLPrecentageLong/100))*10)/PointValue)/10)*pipsize) PositionSizeLong = PositionSizeLong - (PositionSizeLong MOD 0.5)

   

   

   

  

  robertogozzi

  Moderator

  Topics: 69

  Replies: 17188

  Been thanked: 4064 times
  08/25/2019 at 7:00 AM #105483
  BC

  Thanks Robert

  But I found below command was return to nothing.

   

  Example

  Test = 0.5 - ( 0.5 MOD 0.5)

  1	Test = 0.5 - ( 0.5 MOD 0.5)

   

   

  

  BC

  Participant

  Topics: 24

  Replies: 170

  Been thanked: 34 times
  08/25/2019 at 10:06 AM #105496
  robertogozzi

  You are right, the MOD operator only works with integer results.

  Try replacing 100 with 200 in your first line posted.

   

  

  robertogozzi

  Moderator

  Topics: 69

  Replies: 17188

  Been thanked: 4064 times
• Author
  Posts