Defining the number of afterdigits?

• 10/13/2023 at 5:47 PM #222398
  jbrahms10

  Hello,

  I would like to have a predefined number of decimal places for numbers in the screener, e.g. always two. The command I know i.e. “NUMBERFORMAT”, is helping to understand numbers, but the command does not include formating afterdigits.

  Does anyone know a better way of formatting real numbers?

  Thanks

  

  jbrahms10

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  10/13/2023 at 6:02 PM #222399
  JS

  Hi,

  You can use “Round(a, digits)”…

  When you use two for “digits”, there are always two decimal places…

  

  JS

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  10/13/2023 at 7:44 PM #222403
  jbrahms10

  Nope. That doesn’t work.

  

  jbrahms10

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  10/13/2023 at 7:56 PM #222404
  JS

  Hi,

  Thanks for your polite and informative response…

  What doesn’t work for you?

  

  JS

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  10/13/2023 at 8:04 PM #222405
  jbrahms10

   

  This is a very simple code, here you suggest the result will have the number of the digits defined i.e. in this case 2.  The number I apply in brackets doesn’t change anything at all.

  IncreaseCalc = Close/lowest[10]
  Increase = Round(IncreaseCalc, 2)
  SCREENER(Increase as “Increase with 2 afterdigits”)

  Any idea why / how?

  Thank you

   

  

  jbrahms10

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  10/13/2023 at 8:36 PM #222407
  JS

  Hi,

  What the command does is: the second digit is rounded, so what you are left with is a number with up to two significant digits where all subsequent digits are equal to zero…

  The same thing happens with the number in your example, you’re left with a number with two significant digits… (the rest is equal to zero)

  

  JS

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  10/14/2023 at 5:17 AM #222416
  robertogozzi

  @jbrahms10

  Do not double post. Ask your question only once and only in one forum. All double posts will be deleted anyway so posting the same question multiple times will just be wasting your own time and will not get you an answer any quicker. Double posting just creates confusion in the forums.

  Thanks 🙂

   

  

  robertogozzi

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  10/14/2023 at 9:23 AM #222424
  jbrahms10

  Thanks @ JS for clarifying.

  All good now.

   

  1 user thanked author for this post.

  JS

  

  jbrahms10

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