Double bottom or double top

• 05/15/2017 at 12:21 PM #35578
  rama

  Can you one help me with code for double bottom or double top?

  I want the code on any time frame 5 or 20 min or 60 min.

   

  

  rama

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  05/15/2017 at 11:34 PM #35655
  GraHal

  Hi rama

  Hope you get a response. You may want to see my Thread asking for Double Top / Bottom.

  https://www.prorealcode.com/topic/double-top-bottom/

  It’s easy to see the pattern on a Chart, but not easy to code due to variation in number of bars between cycles.

  Cheers
  GraHal

  

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  05/16/2017 at 8:41 PM #35749
  Derek

  Hi rama,

  maybe this approach can be of help:

  If high crosses over highest[x](high) and waitfortop=0 then //x=20 for example waitfortop=1 Currenthigh=high Endif If close < currenthigh and waitfortop=1 then Top=1 Endif If close >= Currenthigh and top=1 then Waitforsecondtop=1 Currenthigh =high Endif If close < currenthigh and Waitforsecondtop=1 then Top=2 Endif If top=2 then Event=1 Endif If top [1]=2 then Top=0 Waitfortop=0 Waitforsecondtop=0 Event=0 Endif Return event

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  If high crosses over highest[x](high) and waitfortop=0 then  //x=20 for example waitfortop=1 Currenthigh=high Endif   If close < currenthigh and waitfortop=1 then Top=1 Endif   If close >= Currenthigh and top=1 then Waitforsecondtop=1 Currenthigh =high Endif   If close < currenthigh and Waitforsecondtop=1 then Top=2 Endif   If top=2 then Event=1 Endif   If top [1]=2 then Top=0 Waitfortop=0 Waitforsecondtop=0 Event=0 Endif   Return event

  Of course this can be cleaned up a lot. But I hope you get the idea.

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  Derek

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  05/17/2017 at 12:01 AM #35755
  Maz

  Yep, the challenge is to write a pattern detector (ie double top/bottom) detector without any hard coded constants (such as x, above) – so as to recognize the pattern regardless of its time duration or volatility. Noise is also an issue.

  When is a possible double top no longer a double top? Define that without constants….

   

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  Maz

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  05/17/2017 at 9:59 AM #35792
  GraHal

  When is a possible double top no longer a double top?

  When price does not go below the low of the trough between the possible double tops?

  

  GraHal

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  05/17/2017 at 10:16 AM #35800
  rama

  As I understand coding for perfect double bottom or double top does  not exist , also practically perfect W or M may not happen in reality.

  Let me rephrase my requirement.

  I have attached the pattern.

  What I am looking is

  I will have two variables

  V1=  Price 1 – price 2

  V2 = absoulute value of price 1- price 3( this absolute because some price 1 may high some time price 3 may be high)

   

  my idea is to trade break outs below price 2

  

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  05/17/2017 at 10:54 AM #35807
  Maz

  Professionally I work with neural networks which feed into trading systems – they look at these patterns like a photo. That’s the best way to detect them. Alas, PRT…  It would be great if PRT could incorporate functions, arrays and better maths in their language – that way some simple pattern training can be written for it. I’m so close to just starting an open source trading language with pattern recognition functions – have to stop myself every day 😀 (because it’s a large project and because time is precious!)

  Back on topic (rant over), I’ll post some code here when I get the chance. Thanks @rama for the input. Will be useful for me too as I do a fair bit of modelling in PRT

   

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  Maz

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  05/17/2017 at 12:10 PM #35816
  rama

  Screen detectors are available for this pattern standard charting packages such as IG or Autochartist.

  if we select the time frame(15 min) and all currencies, software will display all currencies which is currently matching this double top or double bottom pattern.

  My idea to automate my trading instead of screening and placing orders.

  

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  05/17/2017 at 12:59 PM #35823
  Elsborgtrading

  Thats what I’ve been saying for many.. well at least 8 month. Pattern recognision!!

  MAZ you can do it, I’m counting on you!

  😀 Kasper

  Anyway what about Bat, Crab, Cypher patterns, etc.. they all relay on fib. retracements- That should somehow be possible- what your thoughts?

   

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  05/17/2017 at 1:20 PM #35831
  Maz

  Is it a bird? Is it a plane? Is it a duck? Is it Buffet on a jet ski? Maybe it’s all of them? Oh, it’s a complex-chaotic, highly manipulated financial market!

  What am I talking about?

  Check out the screen shots. What do you see? A double top? A triple top? A head and shoulders? Two head and shoulders?

  It’s a triple top whereby the second top is a failed head-and-shoulders and the third top is a successful head-and-shoulders.

  Where do we start?

  if …. then…. ? Or just take a photo and have a bunch of neurons make the decision? 😀

  This was my point about noise. Just something to think about.

  Best,

  M

  

  Maz

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  05/17/2017 at 6:27 PM #35889
  Derek

  The price move can be transfered into all patterns but how many visually perceivable patterns can the code not recognize correct plus the fake signals. In the end we still receive A pattern that can be tested and improved upon. Maybe the way to the big pattern on the higher timeframes is by looking at all the little ones first.

  So, coding pattern recognition indicators is the starting point for further research.

  

  Derek

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  06/04/2017 at 4:17 PM #37389
  Elsborgtrading

  @Maz, ohh well.. at least someone was able to do it.. but if you can’t do it, you know… 😉 Advancepattern

  Okay, the ironic, and poking you pride is over. Being here for a long time, you can just tell when someone is professional, and you are. So I still think you can do it 🙂

  I tried to put this on MT4 platform and it works. I still need to verify if is accurate and how many pattern it recognize. At the start of the post, there is some of the indicators in .Mq4 format and is easy compiled with the compiler described for MT4. perhaps you know to decode it and convert to PRT.

  Though I left the PRT platform I still thought I’d let you know.

  Cheers Kasper

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  Elsborgtrading

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  10/18/2017 at 6:27 AM #49759
  Leo

  Hi all,

  What if the approach for looking to double top/bottoms is first to detect maximum and minimum locals ?

  I have a code that can be use for this goal.

  Here is the theory:

  • We take a moving average
  • We make a second moving average
  • When one crosses the other then, there is a max/min local in that area

  Here I show my indicator (pending of posting approval in the library) and help to locate max/min.

  I will continue to developing this idea for detect doubles top/ bottoms

  Leo Moving Average

  //LEO MOVING AVERAGE //Formula: LMA=WMA+(WMA-SMA) LMA=2*weightedaverage[period](close)-average[period](close) //supports and resistances once support=low once resistance=high smoothLMA=weightedaverage[period](LMA) IF LMA crosses over smoothLMA THEN support=lowest[period](low) ENDIF IF LMA crosses under smoothLMA THEN resistance=highest[period](high) ENDIF support=min(low,support) resistance=max(high,resistance) RETURN LMA AS "LMA", support as "support", resistance as "resistance"

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  //LEO MOVING AVERAGE   //Formula: LMA=WMA+(WMA-SMA) LMA=2*weightedaverage[period](close)-average[period](close)     //supports and resistances once support=low once resistance=high   smoothLMA=weightedaverage[period](LMA)   IF LMA crosses over smoothLMA THEN support=lowest[period](low) ENDIF   IF LMA crosses under smoothLMA THEN resistance=highest[period](high) ENDIF   support=min(low,support) resistance=max(high,resistance)     RETURN LMA AS "LMA", support as "support", resistance as "resistance"

   

   

  

  Leo

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  10/19/2017 at 8:49 PM #49991
  Leo

  Hi all,

  I found a way to detect and locate minimums and maximums local… I think this idea have a lot of potencial

  Here is my code

  Leo Moving Average + minimums&maximums

  //LEO MOVING AVERAGE //Formula: LMA=WMA+(WMA-SMA) LMA=2*weightedaverage[period](close)-average[period](close) //supports and resistances once support=low once resistance=high smoothLMA=weightedaverage[period](LMA) // ---> Storage of minimums and maximums IF BARINDEX>1 THEN IF low < lowest[period](low[1]) THEN mintemp=low //minimum temporal posmintemp=BARINDEX //postition of minimum temporal ENDIF IF high > highest[period](high[1]) then maxtemp=high //maximum temporal posmaxtemp=BARINDEX //position maximum temporal ENDIF ENDIF // --> Detecting and locating a local minimum IF LMA crosses over smoothLMA THEN LEVMIN=mintemp POSLEVMIN=posmintemp support=LEVMIN DRAWARROWUP(POSLEVMIN,LEVMIN) coloured(0,0,0,30) ENDIF // --> Detecting and locating a local maximum IF LMA crosses under smoothLMA THEN LEVMAX=maxtemp POSLEVMAX=posmaxtemp resistance=LEVMAX DRAWARROWDOWN(POSLEVMAX,LEVMAX) coloured(0,0,0,30) ENDIF support=min(low,support) resistance=max(high,resistance) RETURN LMA AS "LMA", support as "support", resistance as "resistance"

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  //LEO MOVING AVERAGE   //Formula: LMA=WMA+(WMA-SMA) LMA=2*weightedaverage[period](close)-average[period](close)     //supports and resistances once support=low once resistance=high   smoothLMA=weightedaverage[period](LMA)     // ---> Storage of minimums and maximums IF BARINDEX>1 THEN IF low < lowest[period](low[1]) THEN mintemp=low //minimum temporal posmintemp=BARINDEX //postition of minimum temporal ENDIF IF high > highest[period](high[1]) then maxtemp=high //maximum temporal posmaxtemp=BARINDEX //position maximum temporal ENDIF ENDIF   // --> Detecting and locating a local minimum IF LMA crosses over smoothLMA THEN LEVMIN=mintemp POSLEVMIN=posmintemp support=LEVMIN DRAWARROWUP(POSLEVMIN,LEVMIN) coloured(0,0,0,30) ENDIF   // --> Detecting and locating a local maximum IF LMA crosses under smoothLMA THEN LEVMAX=maxtemp POSLEVMAX=posmaxtemp resistance=LEVMAX DRAWARROWDOWN(POSLEVMAX,LEVMAX) coloured(0,0,0,30) ENDIF   support=min(low,support) resistance=max(high,resistance)     RETURN LMA AS "LMA", support as "support", resistance as "resistance"

   

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  Leo

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  10/20/2017 at 3:01 PM #50072
  Nicolas

  Hi Leo, this is a good idea, so for now to validate a double top or double bottom we have to fetch through the LEVMIN and LEVMAX previous values if 2 consecutive ones are within the same range, if I follow you idea? This range could be set as a percentage of their values, don’t you think?

  

  Nicolas

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