Ecart pour Point Pivot H1

• 01/26/2019 at 2:19 PM #89700
  TekTonik

  Bonjour,

  J’ai adapté le code donné dans fibonacci-pivots-points-4-hours-daily-weekly-monthly pour calculer le point pivot en H1 :

  J’ai un écart sur certaines heures par rapport au point pivot  H1 natif de PRT, voir screenshot, je ne comprend pas pourquoi auriez vous une idée ?
  tiret pour l’indicateur de PRT PP H1. ligne pour mon indicateur

  Merci pour vos retours

  voici mon code :

  chours = hour=0 or hour=1 or hour=2 or hour=3 or hour=4 or hour=5 or hour=6 or hour=7 or hour=8 or hour=9 or hour=10 or hour=11 or hour=12 or hour=13 or hour=14 or hour=15 or hour=16 or hour=17 or hour=18 or hour=19 or hour=20 or hour=21 or hour=21 or hour=22 or hour=23 if minute=0 and chours then hhigh = Highest[BarIndex - lastHourBarIndex](High)[1] llow = Lowest[BarIndex - lastHourBarIndex](Low)[1] cclose = close[0] lastHourBarIndex = BarIndex[0] endif PP = (hhigh+llow+cclose)/3.0

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  chours = hour=0 or hour=1 or hour=2 or hour=3 or hour=4 or hour=5 or hour=6 or hour=7 or hour=8 or hour=9 or hour=10 or hour=11 or hour=12 or hour=13 or hour=14 or hour=15 or hour=16 or hour=17 or hour=18 or hour=19 or hour=20 or hour=21 or hour=21 or hour=22 or hour=23 if minute=0 and chours then hhigh = Highest[BarIndex - lastHourBarIndex](High)[1] llow = Lowest[BarIndex - lastHourBarIndex](Low)[1] cclose = close[0] lastHourBarIndex = BarIndex[0] endif   PP = (hhigh+llow+cclose)/3.0

   

   

   

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  TekTonik

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  01/27/2019 at 8:54 AM #89725
  fifi743

  bonjour,

  essais

  if chours <> hour then chours = hour hhigh = Highest[BarIndex – lastHourBarIndex](High)[1] llow = Lowest[BarIndex – lastHourBarIndex](Low)[1] cclose = close[0] lastHourBarIndex = BarIndex[0] endif

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  if chours <> hour then   chours = hour hhigh = Highest[BarIndex – lastHourBarIndex](High)[1] llow = Lowest[BarIndex – lastHourBarIndex](Low)[1] cclose = close[0] lastHourBarIndex = BarIndex[0] endif

  et enleve la ligne 1

  cordialement

  

  fifi743

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  05/23/2020 at 10:01 PM #132992
  TekTonik

  Bonjour,

  Solution finalement postée par Nicolas quelque part dans le forum :

   

  /////////////////////////////////////////////////////////// // Pivot Horaire if openhour <>openhour[1] then pphLastHigh = pphHigh pphLastLow = pphLow pphLastClose = close[1] pphHigh = High pphLow = Low pphOpen = open else pphHigh = Max(pphHigh, High) pphLow = Min(pphLow, Low) endif H1PP = (pphLastHigh + pphLastLow + pphLastClose) / 3 H1R1 = 2*H1PP - pphLastLow H1S1 = 2*H1PP - pphLastHigh H1R2 = H1PP + (pphLastHigh - pphLastLow) H1S2 = H1PP - (pphLastHigh - pphLastLow) H1R3 = H1R1 + (pphLastHigh - pphLastLow) H1S3 = H1S1 - (pphLastHigh - pphLastLow)

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  /////////////////////////////////////////////////////////// // Pivot Horaire if openhour <>openhour[1] then pphLastHigh = pphHigh pphLastLow = pphLow pphLastClose = close[1] pphHigh = High pphLow = Low pphOpen = open else pphHigh = Max(pphHigh, High) pphLow = Min(pphLow, Low) endif H1PP = (pphLastHigh + pphLastLow + pphLastClose) / 3 H1R1 = 2*H1PP - pphLastLow H1S1 = 2*H1PP - pphLastHigh H1R2 = H1PP + (pphLastHigh - pphLastLow) H1S2 = H1PP - (pphLastHigh - pphLastLow) H1R3 = H1R1 + (pphLastHigh - pphLastLow) H1S3 = H1S1 - (pphLastHigh - pphLastLow)

   

  

  TekTonik

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  05/27/2020 at 10:20 PM #133518
  Choliver

  Bonsoir à toi,
  Je ne sais pas comment tu fais pour avoir un résultat avec le code proposé ci dessus, mais chez moi il n’y a que des messages d’erreurs.
  Par exemple : “La variable suivante n’est pas utilisée dans le programme : pphopen”
  même chose pour : h1r2 – h1s2 -h1r3 –  h1s3
  Comment ferais-tu obtenir un résultat utilisable ?
  A suivre… 🙂

  

  Choliver

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