Ema in correct sequence

• 11/24/2023 at 4:08 PM #224257
  kvacksa87

  hello. I needed help with a code in ema so that it will buy when ema 5.8.13.21 is in sequence just as I show in the picture. I have written examples 5>8 and 13>21 but I don’t really think it makes the right inputs on the script. Can I write something else?

  

  kvacksa87

  Participant

  Topics: 8

  Replies: 11

  Been thanked: 2 times
  11/24/2023 at 5:14 PM #224260
  robertogozzi

  This is an indicator, just remove the last 5 lines and use UPtrend and DNtrend to tell the position of EMAs:

   

  src = CustomClose Ema5 = average[5,1](src) Ema8 = average[8,1](src) Ema13 = average[13,1](src) Ema21 = average[21,1](src) UPtrend = (Ema5 > Ema8) AND (Ema8 > Ema13) AND (Ema13 > Ema21) DNtrend = (Ema5 < Ema8) AND (Ema8 < Ema13) AND (Ema13 < Ema21) x = UPtrend IF x = 0 THEN x = -DNtrend ENDIF RETURN x coloured by (x) Style(Histogram,1) AS "Trend, 1=UP, 2=DOWN"

  1 2 3 4 5 6 7 8 9 10 11 12

  src     = CustomClose Ema5    = average[5,1](src) Ema8    = average[8,1](src) Ema13   = average[13,1](src) Ema21   = average[21,1](src) UPtrend = (Ema5 > Ema8) AND (Ema8 > Ema13) AND (Ema13 > Ema21) DNtrend = (Ema5 < Ema8) AND (Ema8 < Ema13) AND (Ema13 < Ema21) x = UPtrend IF x = 0 THEN    x = -DNtrend ENDIF RETURN x coloured by (x) Style(Histogram,1) AS "Trend, 1=UP, 2=DOWN"

   

   

  1 user thanked author for this post.

  kvacksa87

  

  robertogozzi

  Moderator

  Topics: 69

  Replies: 17134

  Been thanked: 4031 times
  11/24/2023 at 5:22 PM #224262
  kvacksa87

  Thanks for quick reply it is appreciated

  1 user thanked author for this post.

  robertogozzi

  

  kvacksa87

  Participant

  Topics: 8

  Replies: 11

  Been thanked: 2 times
• Author
  Posts