Finding last two Fractals position

• 06/27/2017 at 4:39 AM #39154
  bmentink

  Hi Guys,

  I am trying to write some code to find the time (index) when the last two low Fractals occurred, or the last two High Fractals occurred.

  I want to use their positional information to calculate Fractal divergence against an indicator.

  I am struggling as the normal Fractal code uses the “lowest” function which works for the last Fractal, but does not allow an offset to find the 2nd to last Fractal.

  Any help much appreciated.

  B.

  

  bmentink

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  06/27/2017 at 1:49 PM #39222
  Nicolas

  You can make a new variable that store the previous high fractal barindex if a new high one is found. This way, you should be able to compare the current fractal barindex to the previous one stored in a variable.

  

  Nicolas

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  06/27/2017 at 8:02 PM #39248
  bmentink

  Thanks Nicolas,

  I am having trouble with how to store the previous Fractal, in the code snippet (just the low Fractal):

  Previous Fractal

  cp = 2 //(default) PreviousLF = -1 if low[cp] <= lowest[2*cp+1](low) then CurrentLF = barindex else CurrentLF = -1 endif

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  cp = 2 //(default)   PreviousLF = -1   if low[cp] <= lowest[2*cp+1](low)  then CurrentLF = barindex else CurrentLF = -1 endif

  I don’t know how/when to save the CurrentLF to PreviousLF

  Cheers

   

  

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  06/28/2017 at 10:15 AM #39279
  Nicolas

  You could do it this way instead:

  cp = 2 //(default) if low[cp] <= lowest[2*cp+1](low) then PreviousLF = CurrentLF CurrentLF = barindex endif

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  cp = 2 //(default)   if low[cp] <= lowest[2*cp+1](low)  then PreviousLF = CurrentLF CurrentLF = barindex endif

  So now you have continuously a set of 2 low fractals barindex stored.

  

  Nicolas

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  06/28/2017 at 8:01 PM #39337
  bmentink

  Thanks Nicolas, wasn’t thinking 😉

  

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  10/13/2020 at 10:41 PM #147345
  Monochrome

  Hi im trying to find the values of the previous THREE factals. Having trouble.

  cp = 20 if high[cp] >= highest[2*cp+1](high) then pprevioushf = PrevioushF PrevioushF = CurrentHF CurrentHF = barindex endif if low[cp] <= lowest[2*cp+1](low) then ppreviouslf = PreviousLF PreviousLF = CurrentLF CurrentLF = barindex endif TOPy = high[currenthf] TOPy1 = high[previoushF] TOPy2 = high[pprevioushF] BOTy = low[currentLF] BOTy1 = low[previousLF] BOTy2 = low[ppreviouslf

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  cp = 20 if high[cp] >= highest[2*cp+1](high) then pprevioushf = PrevioushF PrevioushF = CurrentHF CurrentHF = barindex endif if low[cp] <= lowest[2*cp+1](low)  then ppreviouslf = PreviousLF PreviousLF = CurrentLF CurrentLF = barindex endif   TOPy = high[currenthf] TOPy1 = high[previoushF] TOPy2 = high[pprevioushF] BOTy = low[currentLF] BOTy1 = low[previousLF] BOTy2 = low[ppreviouslf

  Can somebody help me?

  

  Monochrome

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  10/14/2020 at 12:13 AM #147351
  robertogozzi

  This Nicolas’code modified to accomodate for another two places:

  if low[cp] <= lowest[2*cp+1](low) then Previous3LF = Previous2LF Previous2LF = Previous1LF Previous1LF = CurrentLF CurrentLF = barindex endif

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  if low[cp] <= lowest[2*cp+1](low)  then Previous3LF = Previous2LF Previous2LF = Previous1LF Previous1LF = CurrentLF CurrentLF   = barindex endif

  so you can now access Previous1LF, Previous2LF and Previous3LF.

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  Monochrome

  

  robertogozzi

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  10/14/2020 at 12:19 AM #147353
  Monochrome

  Thankyou for your reply.

  If i want to find the value(high or low) of a previous factal such as ‘previous3LF’, is this code correct?

  Top3 = high[previous3LF]

  1	Top3 = high[previous3LF]

   

  

  Monochrome

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  10/14/2020 at 12:42 AM #147356
  robertogozzi

  No, you should write:

  Top3 = high[BarIndex - previous3LF]

  1	Top3 = high[BarIndex - previous3LF]

  Because if now it’s BarIndex 100 and previous3LF is 81, then you have to access the 19th previous bar to get the correct value.

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  Monochrome

  

  robertogozzi

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