Higer exponential average

• 07/04/2024 at 6:23 PM #234797
  Ludde

  Hi; I wonder if You can help me with this.

  I would like to have a proscreener with the following conditions:

  1. An 8-day exponential moving average (EMA) that is turning upwards.
  2. The 8-day EMA must also be higher than the last time the 8-day EMA turned upwards.

   

  

  Ludde

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  07/04/2024 at 7:45 PM #234802
  robertogozzi

  There you go:

  ONCE CurrTurn = 0 ONCE PrevTurn = 0 Cond = 0 Sma8 = average[8](close) UPturn = (Sma8 > Sma8[1]) AND (Sma8[1] < Sma8[2]) IF UPturn THEN PrevTurn = CurrTurn CurrTurn = Sma8 IF CurrTurn > PrevTurn THEN Cond = 1 ENDIF ENDIF SCREENER[Cond]

  1 2 3 4 5 6 7 8 9 10 11 12 13

  ONCE CurrTurn = 0 ONCE PrevTurn = 0 Cond = 0 Sma8 = average[8](close) UPturn = (Sma8 > Sma8[1]) AND (Sma8[1] < Sma8[2]) IF UPturn THEN    PrevTurn = CurrTurn    CurrTurn = Sma8    IF CurrTurn > PrevTurn THEN       Cond = 1    ENDIF ENDIF SCREENER[Cond]

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  Iván

  

  robertogozzi

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  07/06/2024 at 2:07 PM #234840
  Ludde

  Thank you for helping me, but it doesn´t work for me. I gets all kind of different hits.

  

  Ludde

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  07/06/2024 at 6:27 PM #234860
  robertogozzi

  My bad, I incorrectly coded SMA instead of EMA.

  This is correct:

  ONCE CurrTurn = 0 ONCE PrevTurn = 0 Cond = 0 Ema8 = average[8,1](close) UPturn = (Ema8 > Ema8[1]) AND (Ema8[1] < Ema8[2]) IF UPturn THEN PrevTurn = CurrTurn CurrTurn = Ema8 IF CurrTurn > PrevTurn THEN Cond = 1 ENDIF ENDIF SCREENER[Cond]

  1 2 3 4 5 6 7 8 9 10 11 12 13

  ONCE CurrTurn = 0 ONCE PrevTurn = 0 Cond = 0 Ema8 = average[8,1](close) UPturn = (Ema8 > Ema8[1]) AND (Ema8[1] < Ema8[2]) IF UPturn THEN    PrevTurn = CurrTurn    CurrTurn = Ema8    IF CurrTurn > PrevTurn THEN       Cond = 1    ENDIF ENDIF SCREENER[Cond]

  1 user thanked author for this post.

  Ludde

  

  robertogozzi

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