High volume beginning of session
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- This topic has 32 replies, 4 voices, and was last updated 1 year ago by JS.
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09/20/2023 at 10:50 AM #221320Hello,I would like to see all the stocks that meet this requirement:
- The first half hour volume of trading day is more than 50% of the average daily volume over last 30 days
- The average daily volume of the last 30 days needs to be at least 250000
- The stockprice needs to be above 4
Thanks
gr Marco
09/20/2023 at 11:26 AM #221321This is set for the 5-mn TF (you can change N for other TFs):
123456789101112Timeframe(Daily)VolAvg = average[30,0](volume)//Timeframe(default)N = 6 //1=30mn-TF, 2=15mn-TF, 3=10mn-TF, 6=5mn-TF, 30=1mn-TFFirstHalfHour = 093000IF OpenTime = FirstHalfHour THENc1 = (summation[N](volume)) > (VolAvg / 2)ENDIFc2 = close > 4Cond = c1 AND c2SCREENER[Cond](VolAvg AS "Vol average")09/20/2023 at 11:36 AM #22132209/20/2023 at 11:44 AM #221324At line 6 you must write when the first HALF HOUR ends.
edited
09/20/2023 at 11:46 AM #221325Also, in line 7 replace OPENTIME with TIME.
09/20/2023 at 3:12 PM #22133809/22/2023 at 1:00 PM #22144809/23/2023 at 11:07 AM #221467There are some issues:
- to work on a 30-minute boundary, you must use a 30-minute (or lower) TF
- it’s (almost) impossible that a 30-minute VOLUME be > the average volume of the last 30 days!
Anyway, the previous code had a few bugs, this the updated code:
1234567891011121314Timeframe(Daily)VolAvg = average[30,0](volume)c1 = VolAvg > 250000//Timeframe(default)N = 1 //1=30mn-TF, 2=15mn-TF, 3=10mn-TF, 6=5mn-TF, 30=1mn-TFFirstHalfHour = 153000c2 = 0IF OpenTime = FirstHalfHour THENc2 = summation[N](volume) > (VolAvg / 2)ENDIFc3 = close > 4Cond = c1 AND c2 AND c3SCREENER[Cond](VolAvg AS "Vol average")Selecting ALL the security lists, I was returned just 2 signals.
09/24/2023 at 9:44 AM #22149009/24/2023 at 5:25 PM #221517What do you mean, what average is it?
09/25/2023 at 9:31 AM #22154509/25/2023 at 3:31 PM #221569Hi Roberto,
It is the 30 day average DAILY volume not the 30day average volume.
I know what I wrote. What I can’t understand is what your quoted sentence means!
You are talking about the SAME average, how can they be different from each other?
09/26/2023 at 8:01 AM #22159509/26/2023 at 3:28 PM #22161709/27/2023 at 11:00 AM #221665Try explaining again your conditions as a list (I may have misunderstood some of them).
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