HORIZONTAL BOX CHANNEL

• 12/02/2016 at 11:12 PM #17740
  GraHal

  I can’t think how to code a screener to detect a ‘consolidation range’ similar to attached.

  Anybody seen code to do the job on here or got any ideas please?

  Many Thanks
  GraHal

   

  

  GraHal

  Participant

  Topics: 211

  Replies: 8774

  Been thanked: 2180 times
  12/03/2016 at 1:34 PM #17758
  Nicolas

  You can try to test the difference in points between the highest high and lowest low over last X periods.

  

  Nicolas

  Keymaster

  Topics: 81

  Replies: 20863

  Been thanked: 4773 times
  12/03/2016 at 3:43 PM #17762
  GraHal

  I’ve done the two below (some of your code I’m sure, Nicolas) but they may or may not result in a horizontal pattern.

   

  hh = highest[60](high)[1] ll = lowest[60](low)[1] C1 = (hh-ll)<10*pipsize C2 = Open > High[1] OR Open < Low[1] Screener [C1 and C2] (hh-ll AS "Range")

  1 2 3 4 5 6 7 8

  hh = highest[60](high)[1] ll = lowest[60](low)[1]   C1 = (hh-ll)<10*pipsize   C2 = Open > High[1] OR Open < Low[1]   Screener [C1 and C2]  (hh-ll AS "Range")

   

  fast = average[10](close) slow = average[40](close) spread = ((fast/slow)-1)*100 flatrange = ABS((lowest[60](low)-highest[60](high))/close)*100 c1 = fast>slow AND spread<10 AND close>fast AND flatrange<=15 SCREENER[c1] (flatrange as "Range")

  1 2 3 4 5 6 7 8

  fast = average[10](close) slow = average[40](close) spread = ((fast/slow)-1)*100 flatrange = ABS((lowest[60](low)-highest[60](high))/close)*100   c1 = fast>slow AND spread<10 AND close>fast AND flatrange<=15   SCREENER[c1] (flatrange as "Range")

   

  

  GraHal

  Participant

  Topics: 211

  Replies: 8774

  Been thanked: 2180 times
  12/03/2016 at 8:26 PM #17766
  Nicolas

  I don’t know about the second one, but for the first one, it would do the job. You should look further back in the past?

  

  Nicolas

  Keymaster

  Topics: 81

  Replies: 20863

  Been thanked: 4773 times
• Author
  Posts