how to count zigzag moves

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05/22/2023 at 4:59 PM #215033 quote

renzocarioca
Participant

Junior

Hi

I would like to count the quantity of zigzag moves of an index/security of a chart

ex: zigzag moves of 5% of the SPX index

I have tried a few things but what I get is kind strange, is it possible? The last attempt was this one but it gives an error message (the following variable is undefined: count )

thank you

a= ZigZagPoint[10](close)
b=count[a]
c=cumsum (b)
return c

05/22/2023 at 6:33 PM #215034 quote
robertogozzi
Moderator

Legend
Firstly, COUNT is not defined anywhere thus can’t be used.

Secondly, ZIGZAG returns a value each bar, it doesn’t count swing points, so counting it will return a huge number.

Thirdly, you can count swing points with this code, but it’s useless as it’s a repainting, so it may change any swing point several bars after they have already been counted as you will easily spot on a 1-second TF (see my attached pic):
```
ONCE Count = 0
myZZ    = ZigZagPoint[10](close)
SwingHI = (myZZ < myZZ[1]) AND (myZZ[1] > myZZ[2])
SwingLO = (myZZ > myZZ[1]) AND (myZZ[1] < myZZ[2])
IF SwingHI OR SwingLO THEN
   c = c + 1
ENDIF
return c AS "Count"
```
ZigZag-count.jpg
05/22/2023 at 6:34 PM #215036 quote
JS
Participant

Master
(Sorry same time as Roberto)
Hi,

You can try this one…

I think the calculation of the ZigZag is incorrect, for example if I set a 5% change (from bottom to top or vice versa) then the number of change (points) is incorrect…??
```
PercentChange=5

ZZ=ZigZag[PercentChange](Close)

If ZZ[1]<ZZ[2] and ZZ>ZZ[1] then
BottomCount=BottomCount+1
ElsIf ZZ[1]>ZZ[2] and ZZ<ZZ[1] then
TopCount=TopCount+1
EndIf

TotalCount=BottomCount+TopCount

Return BottomCount as "BottomCount", TopCount as "TopCount", TotalCount as "TotalCount"
```
Schermafbeelding-2023-05-22-om-19.32.28.png
05/23/2023 at 5:18 AM #215045 quote
renzocarioca
Participant

Junior
Thank you it works, just return totalcount
```
PercentChange=5


ZZ=ZigZag[PercentChange](Close)


If ZZ[1]<ZZ[2] and ZZ>ZZ[1] then
BottomCount=BottomCount+1
ElsIf ZZ[1]>ZZ[2] and ZZ<ZZ[1] then
TopCount=TopCount+1
EndIf


TotalCount=BottomCount+TopCount


Return BottomCount as "BottomCount", TopCount as "TopCount", TotalCount as "TotalCount"
```
05/23/2023 at 11:25 AM #215058 quote

robertogozzi
Moderator

Legend

Two is better than one 🙂
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