Low and following lower low in weekly timeframe

• 09/29/2023 at 6:33 PM #221822
  JEA

  Hi. I am trying to get an screener that give me, in a weekly timeframe, a low followed by another low, lower than the previous one. I am afraid that I am doing something wrong, probably due to my lack of expertise.

  Insert PRT code

   

  My code is the following:

   

  Timeframe (weekly)

  c1= lowest [0] (low) < lowest [1] (low [1]), being 0 the latest bar and 1 the previous to the latest bar.

  screener [c1]

   

  I would appreciate your help.

  

  JEA

  Participant

  Topics: 7

  Replies: 16

  Been thanked: 2 times
  09/29/2023 at 8:02 PM #221832
  JS

  Hi @JEA

  Try this one…

  Lower than last week

  TimeFrame(Weekly) C1=Low<Low[1] SCREENER[C1](Low as "Low")

  1 2 3

  TimeFrame(Weekly) C1=Low<Low[1] SCREENER[C1](Low as "Low")

  

  JS

  Participant

  Topics: 26

  Replies: 1701

  Been thanked: 768 times
  09/29/2023 at 8:28 PM #221833
  JEA

  Thank you very much for your quick answer.

  I’ve tried your solution and it works sometimes but not always. Do you know any alternative to get that the last bar low would be lower than the previous one?

   

  All my best,

  

  JEA

  Participant

  Topics: 7

  Replies: 16

  Been thanked: 2 times
  09/29/2023 at 8:37 PM #221834
  JS

  Hi,

  Can you point out where it doesn’t work…?
  It’s a simple solution that should work in any circumstance…

  (Did you select “weekly” in your screener…?)

  

  JS

  Participant

  Topics: 26

  Replies: 1701

  Been thanked: 768 times
  09/29/2023 at 8:54 PM #221836
  JEA

  I will try to explain it. I am afraid that I have not been very clear since the beginning. Apologize for it.

  I want to get a double bottom, being the second low lower than the previous one.

  It is one of the conditions of the screener but the others are already solved.

  This is why I tried c1= lowest [0] (low) < lowest [1] (low [1]),

  because I wanted the last bar as the lowest and the previous one with a higher low. May be I should have defined a period as 52 weeks or so.

  I hope to have been more clear now.

   

   

   

  

  JEA

  Participant

  Topics: 7

  Replies: 16

  Been thanked: 2 times
  09/29/2023 at 9:18 PM #221837
  JS

  Hi,

  It is indeed possible to compare the last “Low” with a previous period, for example 52 weeks…
  You can see the lowest “Low” in the designated column of the results sheet…

  Low < Previous Period

  TimeFrame(Weekly) C1=Low<Lowest[52](Low[1]) SCREENER[C1](Lowest[52](Low[1]) as "Lowest52")

  1 2 3

  TimeFrame(Weekly) C1=Low<Lowest[52](Low[1]) SCREENER[C1](Lowest[52](Low[1]) as "Lowest52")

  

  JS

  Participant

  Topics: 26

  Replies: 1701

  Been thanked: 768 times
  09/30/2023 at 7:51 AM #221855
  JEA

  It works now!! Thanks a lot for your help.

  1 user thanked author for this post.

  JS

  

  JEA

  Participant

  Topics: 7

  Replies: 16

  Been thanked: 2 times
• Author
  Posts