Lowest from Y1 to Y2

• 03/10/2022 at 1:49 PM #189750
  ZeroCafeine

  Hi all,

  I saw the Lowest fonction can find a lowest of a variable on the last X periodes for exemple, but how to find a lowest between 2 barindex for exemple between Y1 and Y2 ?
  for exemple on this photo how to find the lowest Low between Candle[5] and Candle[36] ( Y2=36 / Y1=5) ?

   

  entre ces 2 valeurs

  

  ZeroCafeine

  Participant

  Topics: 115

  Replies: 477

  Been thanked: 43 times
  03/10/2022 at 1:56 PM #189752
  JC_Bywan

  From 5 to 36, there are 36-5+1 = 32 candles, we simply ask what was 5 candles ago the lowest among 32:

  a=lowest[32](low) b=a[5] return b

  1 2 3 4

  a=lowest[32](low) b=a[5]   return b

   

  1 user thanked author for this post.

  ZeroCafeine

  

  JC_Bywan

  Moderator

  Topics: 20

  Replies: 2651

  Been thanked: 917 times
  03/10/2022 at 2:00 PM #189753
  JC_Bywan

  or if you want to easily change Y1 and Y2 (with Y2>Y1 implied, haven’t added an IF statement to protect against the opposite):

  Y1=5 Y2=36 a=lowest[Y2-Y1+1](low) b=a[Y1] return b

  1 2 3 4 5 6

  Y1=5 Y2=36 a=lowest[Y2-Y1+1](low) b=a[Y1]   return b

   

  1 user thanked author for this post.

  ZeroCafeine

  

  JC_Bywan

  Moderator

  Topics: 20

  Replies: 2651

  Been thanked: 917 times
  03/10/2022 at 3:56 PM #189767
  JS

  Lowest Low between candle[5] and candle[36]:

  a = Lowest[36](Low[5])

  1 user thanked author for this post.

  ZeroCafeine

  

  JS

  Participant

  Topics: 26

  Replies: 1720

  Been thanked: 783 times
  03/11/2022 at 12:22 PM #189798
  ZeroCafeine

  tks to all for your answers,

  and how to get the barindex number of this lowest candle ?

  I saw some solution like doing a For y = 0 to 38 for exemple and compare the Lowest we get before with your solution with the Low[y] of each candle for get the barindex, but maybe they have other short soluttion ?

  

  ZeroCafeine

  Participant

  Topics: 115

  Replies: 477

  Been thanked: 43 times
  03/11/2022 at 12:56 PM #189801
  robertogozzi

  There you go:

  x = LowestBars[36](low[5]) //HighestBars for the highest

  1	x = LowestBars[36](low[5])   //HighestBars for the highest

  1 user thanked author for this post.

  ZeroCafeine

  

  robertogozzi

  Moderator

  Topics: 69

  Replies: 17150

  Been thanked: 4039 times
  03/11/2022 at 1:25 PM #189803
  ZeroCafeine

  tks for your answer but I’m totaly confused, I don’t understand why it’s not working or mabt I don’t know how to use it, with my result I find the barindex 21 the blue cyrcle but with yous I find barindex = 8 the red cyrcle, where I’m wrong ? I want the fast solution for using less of computer ic

  Defparam drawonlastbaronly = true a = Lowest[36](Low[13]) // Roberto Solution x = LowestBars[36](low[13]) For i = 0 to 36 Do IF Low[i] = a Then X1 = i drawtext("Barindex = #i#",barindex[i],Low[i]) // Roberto Barindex drawtext("Barindex = #x#",barindex[x],Low[x]) break ENDIF Next Return

  1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18

  Defparam drawonlastbaronly = true   a = Lowest[36](Low[13])   // Roberto Solution x = LowestBars[36](low[13])   For i = 0 to 36 Do IF Low[i] = a Then X1 = i drawtext("Barindex = #i#",barindex[i],Low[i]) // Roberto Barindex drawtext("Barindex = #x#",barindex[x],Low[x]) break ENDIF Next   Return

  Best Reguards

  

  ZeroCafeine

  Participant

  Topics: 115

  Replies: 477

  Been thanked: 43 times
  03/11/2022 at 1:34 PM #189805
  ZeroCafeine

  This is my Elder Triple screen now and headache, I’m sure your solution will be on 2 or 3 lines 🤣🤣🤣

  

  ZeroCafeine

  Participant

  Topics: 115

  Replies: 477

  Been thanked: 43 times
  03/11/2022 at 2:36 PM #189807
  robertogozzi

  Use

  IF Low[i+13]

  1	IF Low[i+13]

   

  1 user thanked author for this post.

  ZeroCafeine

  

  robertogozzi

  Moderator

  Topics: 69

  Replies: 17150

  Been thanked: 4039 times
  03/11/2022 at 4:33 PM #189809
  ZeroCafeine

  I don’t know why I don’t know to use you solution, but I found this one :

  Defparam drawonlastbaronly = true a = Lowest[36](Low[13]) // Roberto Solution x = LowestBars[36](low[13]) Roberto = 13 + x IF X Then drawtext("RobertoIndex = #Roberto#",barindex[Roberto],Low[Roberto]) ENDIF Return

  1 2 3 4 5 6 7 8 9 10 11 12 13

  Defparam drawonlastbaronly = true   a = Lowest[36](Low[13]) // Roberto Solution x = LowestBars[36](low[13])   Roberto = 13 + x   IF X Then drawtext("RobertoIndex = #Roberto#",barindex[Roberto],Low[Roberto]) ENDIF   Return

  if I  the drawtext fonction with out IF condition, I get error because the LowestBars fonction can get -1 as a result

  now the good barindex is 22 instead 21 because I got one candle more in H4 TF

  

  ZeroCafeine

  Participant

  Topics: 115

  Replies: 477

  Been thanked: 43 times
  03/11/2022 at 5:18 PM #189813
  robertogozzi

  Because the 13th bar is bar 12 (0 to 12 is 13 bars), so you will have to adjust your calculations.

   

  1 user thanked author for this post.

  ZeroCafeine

  

  robertogozzi

  Moderator

  Topics: 69

  Replies: 17150

  Been thanked: 4039 times
  03/11/2022 at 5:28 PM #189814
  JS

  From 0 to 13 is 14 bars so use:

  Roberto = 14 + x

  

  JS

  Participant

  Topics: 26

  Replies: 1720

  Been thanked: 783 times
  03/12/2022 at 8:39 AM #189842
  JC_Bywan

  It is of course possible I misunderstood the initial query, or even if I hadn’t I would easily concede perhaps I made the explanation too short alongside my proposal. But I would have to respectfully disagree with the other proposal.

  If you write:  a = Lowest[36](Low[5]) , it doesn’t give you the lowest low between candle[5] and candle[36], it would give the lowest low below candle[5] and candle[41], because at candle[36] what was lowest[5] at that time is a lowest[41] seen from now. So on one hand yes it would easily get rid of unwanted candles[0] through [4] in the search, but on the other hand it adds unwanted extra 5 candles [37] through [41] beyond [36].

  Which is why I suggested: to first assess the span of the search (Y2–Y1+1 = 36-5+1 = 32 candles wide), to search that span for lowest low (that’s “a”), and from there to offset it by Y1=5 (that’s “b”), with:

  Y1=5 Y2=36 a=lowest[Y2-Y1+1](low) b=a[Y1]

  1 2 3 4

  Y1=5 Y2=36 a=lowest[Y2-Y1+1](low) b=a[Y1]

  as a way of eliminating candles [0] through [4] and simultaneously avoiding addition of unwanted extra candles beyond Y2 at the other end of the spectrum in the search interval.

  1 user thanked author for this post.

  ZeroCafeine

  

  JC_Bywan

  Moderator

  Topics: 20

  Replies: 2651

  Been thanked: 917 times
  03/12/2022 at 10:05 AM #189848
  JS

  Hi @JC_Bywan,

  You are right about adding 5 extra candles…

  The starting point is low[5] and from there your look back period is [36] = 5 + 36

  So this must also give the right answer: a = Lowest[Y2-Y1+1](Low[Y1])

   

   

   

   

  1 user thanked author for this post.

  ZeroCafeine

  

  JS

  Participant

  Topics: 26

  Replies: 1720

  Been thanked: 783 times
  03/12/2022 at 7:48 PM #189887
  JS

  Perhaps a system can be made of this?

  When you know where the Lowest Low (LL) and the Highest High (HH) occur, you can say in the simplest form;

  When the HH occurs after the LL then you are in an ascending phase and vice versa when the LL occurs after the HH then you are in a downward phase.

  With the formulas:

  LLBar = LowestBars[n](Low) you determine the bar where the LL occurs

  HHBar = HighestBars[n](High) you determine the bar where the HH occurs

  When LLBar > HHBar (Bullish)

  When LLBar < HHBar (Bearish)

  Of course, this is the simplest form but maybe with MTF, SL, TP, etc. we can improve this system.

  LLBar HHBar

  DefParam CumulateOrders = False LLBar = LowestBars[n](Low) HHBar = HighestBars[n](High) If LLBar > HHBar then Buy 1 Contracts at Market ElsIf LlBar < HHBar then SellShort 1 Contracts at Market EndIf Graph LLBar as "LowestBar" Graph HHBar as "HighestBar"

  1 2 3 4 5 6 7 8 9 10 11 12 13

  DefParam CumulateOrders = False   LLBar = LowestBars[n](Low) HHBar = HighestBars[n](High)   If LLBar > HHBar then Buy 1 Contracts at Market ElsIf LlBar < HHBar then SellShort 1 Contracts at Market EndIf   Graph LLBar as "LowestBar" Graph HHBar as "HighestBar"

   

  1 user thanked author for this post.

  ZeroCafeine

  

  JS

  Participant

  Topics: 26

  Replies: 1720

  Been thanked: 783 times
• Author
  Posts