MACD screener to code

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02/10/2017 at 12:50 AM #24588 quote
SAM
Participant

Senior
Hi Nicolas,

Could you help me to code a screener with this conditions?
1. Macd ligne >0
2. When 1) in true within next 6 bars, close break-out the high of the last 10 bars
Thank-you!!
02/10/2017 at 9:23 AM #24605 quote
Nicolas
Keymaster

Legend
Here is the code you are requested, the MACD was at least 6 bars above 0 and the Close of the current candlestick is breaking the highest high of the last 10 bars:
```
m = summation[6](macd[12,26,9]>0)=6
b = close crosses over highest[10](high)[1]

screener [m and b]
```
Not tested, please tell us if it’s working ok for you.
02/13/2017 at 6:56 PM #24992 quote
SAM
Participant

Senior
Hi Nicolas, sorry for the delay.. Thanks very much for your answer… and for your time!!
I tried your code and work verygood!!
But my mistake, I actually wanted to ask that the condition “b” is verified within 6 bar since when macd[12,26,9] crosses over 0. (Not only >0)
This code with the condition macd[12,26,9]>0 finds a many shares.

I tried to write a code, but not work good… could you help me? Thank very much!!
```
a = macd[12,26,9]
c1= a crosses over 0

if c1 then
m = summation[6](a>0)=6
b = close crosses over highest[10](high)[1]
endif


screener [m and b]
```
02/13/2017 at 8:20 PM #24996 quote
Nicolas
Keymaster

Legend
This modified code should do the trick:
```
a = macd[12,26,9]
c1= a crosses over 0

m = summation[6](c1)>0
b = close crosses over highest[10](high)[1]

screener [m and b]
```
02/15/2017 at 3:15 PM #25152 quote
SAM
Participant

Senior
Dear Nicolas, so work very good!! It’s just that I needed!!
I wrote a screener (long or Short)
```
once direction =0
a = macd[12,26,9]
c1= a crosses over 0
c2 = a crosses under 0
m = summation[6](c1)>0
n = summation[6](c2)>0
b1 = close crosses over highest[10](high)[1]
b2 = close crosses under Lowest[10](low)[1]

if m and b1 then
direction=1
endif
if n and b2 then
direction=-1
endif


screener [(m and b1) or (n and b2)](direction)
```
Could I make a new library screener?
02/15/2017 at 7:42 PM #25202 quote

Nicolas
Keymaster

Legend

Of course you can! Please do it! 🙂 I’m happy to know it suits your needs. Please add a little description of the screener when you’ll post it into the code library. Thanks in advance.
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