Need help with Date

• 02/13/2024 at 3:19 PM #228059
  kingmordecai

  Hello to All,

   

  Date is in the format YYYYMMDD

  is there a way to take a date and algorithmically extract the year, month and day

  Or is there a way to get the number of days between two days?

  When I PRINT(19800220 – 19791215) I get the mathematically correct answer of 8886 but not the number of days

  Also is there a way to algorithmically to convert a date to days?

  It seems all of the temporal functions correspond to the bar number but only for the bars in your history, what I am looking for are ways to calculate these things independent of bar history

   

  Thank you for your Time

  Scott

   

  

  kingmordecai

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  02/13/2024 at 5:13 PM #228085
  robertogozzi

  Here is s snippet to retrieve tha DAY and MONTH https://www.prorealcode.com/topic/tomorrows-date/#post-94733.

  A Date is just an 8-digit number in the format YYYYMMDD.

  To retrieve the DAY simply divide it by 100 truncating the result. Multiply the result by 100 and The DAY is the difference between the result and the original date.

  Use the latter result in the format YYYYMM00 and divide it by 10000, truncating the result. You’ll get YYYY0000. The difference between the two numbets, divided by 100, is the MONTH.

  You can retrieve the YEAR with yhe result YYYY0000 MOD 10000.

   

   

  

  robertogozzi

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  02/13/2024 at 5:16 PM #228086
  robertogozzi

  Computing a difference between two dates or times is quite complicated and would require several tens of lines.

   

  

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  02/13/2024 at 5:19 PM #228087
  robertogozzi

  To truncate a division, use FLOOR(dividend/divisor,0).

   

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  kingmordecai

  

  robertogozzi

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  02/13/2024 at 6:58 PM #228103
  kingmordecai

  Thanks Roberto,

  to convert a Date into Year, Month, & Day from what you stating this works

  TheDate = 20240213 TheYear = Floor(TheDate / 10000, 0) TempDay = Floor(TheDate / 100, 0) TheDay = ((TheDate / 100) - TempDay) * 100 TempMonth = Floor(TheDate / 100, 0) * 100 TempMonth2 = TempMonth / 10000 TheMonth = (TempMonth2 - Floor(TempMonth / 10000, 0)) * 100 PRINT(TheYear) PRINT(TheMonth) PRINT(TheDay)

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  TheDate = 20240213 TheYear = Floor(TheDate / 10000, 0) TempDay = Floor(TheDate / 100, 0) TheDay = ((TheDate / 100) - TempDay) * 100   TempMonth = Floor(TheDate / 100, 0) * 100 TempMonth2 = TempMonth / 10000 TheMonth = (TempMonth2 - Floor(TempMonth / 10000, 0)) * 100   PRINT(TheYear) PRINT(TheMonth) PRINT(TheDay)

  So that is working thank you!

   

  It seems to me that to work with Dates will be very cumbersome in the way that RealTimePro has the Date keyword programmed.

  My main goal is write a function where I pass it two normal dates or Unix Time stamps or excel serial date numbers and it returns the number of days between the two.

  Does anyone have any ideas on how I can go about programming this type of functionality?

  Thank you for your Time

  Scott

  

  kingmordecai

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  02/13/2024 at 7:07 PM #228104
  kingmordecai

  ok I think I will just tackle this by using the number days elapsed from Jan 1st 1900 and keep all of my references to dates in the format of days since that date.

   

  Again thanks to Roberto, for helping me visualize how to tackle my problem!

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  kingmordecai

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  02/14/2024 at 10:41 AM #228150
  robertogozzi

  You can do some math with seconds between two dates using the timestamp system constant https://www.prorealcode.com/documentation/timestamp/.

   

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  02/14/2024 at 12:01 PM #228163
  kingmordecai

  Hello Roberto,

   

  Thats exactly what I ended up doing. 🙂

  How I am handling this

  // I pass into the indicator a serial number of the date I am interested in // this Offset is positive if the date in question is after Jan 1st, 1970 // and negative if the date is before Jan 1st, 1970 Count = Floor(OpenTimestamp/86400,0) - Offset

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  // I pass into the indicator a serial number of the date I am interested in // this Offset is positive if the date in question is after Jan 1st, 1970 // and negative if the date is before Jan 1st, 1970 Count = Floor(OpenTimestamp/86400,0) - Offset

  This has exactly what I need

  Again thanks for the help and guidance

  Scott

  

  kingmordecai

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