Steep angle up

Viewing 5 posts - 1 through 5 (of 5 total)

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02/23/2024 at 10:39 AM #228617 quote
marco7630
Participant

New
Hi,

I would to see all the stocks on a daily time frame that fit the following criteria
1. The angle of the EMA10 daily over the last 5 days should be at least 45% (up)
2. The EMA200 daily has been rising for at least 20 days
Thanks

Gr Marco
02/24/2024 at 11:52 AM #228683 quote
JS
Participant

Master
Hi Marco,

Determining an angle, for example 45 degrees, is difficult…
An alternative could be:
The EMA10 is up at least 45% over the last five days…
```
TimeFrame(Daily)
EMA10=ExponentialAverage[10](Close)
EMA200=ExponentialAverage[200](Close)

C1=(EMA10-EMA10[5])/EMA10[5]*100>=45
C2=Summation[20](EMA200>EMA200[1])=20

Screener[C1 and C2]
```
Schermafbeelding-2024-02-24-om-11.50.18.png
02/24/2024 at 12:55 PM #228685 quote
marco7630
Participant

New
Hi JS,

Is it possible to say:
- The EMA10 is up at least 5 times daily ATR percentage over the last 5 days
Furthermore is it possible to add dates in the code?

For example. I want to see at the stocks that meet the requirements on 13-12-23?

Gr Marco
02/24/2024 at 2:15 PM #228692 quote
JS
Participant

Master
Hi Marco,

Here is the custom screener…
It is possible to use dates in your screener, but you must consider the maximum history of a screener…
In this case, you’re using an EMA200 that already uses (much) more history, and when you also investigate the past, you’re probably short of history…
```
TimeFrame(Daily)

//If Date=20231213 then

EMA10=ExponentialAverage[10](Close)
EMA200=ExponentialAverage[200](Close)
ATR5=AverageTrueRange[5](Close)

C1=(EMA10-EMA10[5])>=5*ATR5
C2=Summation[20](EMA200>EMA200[1])=20

//EndIf

Screener[C1 and C2]
```
02/26/2024 at 7:59 PM #228785 quote

marco7630
Participant

New

Thanks JS
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