Stock Gap Screener

• 11/21/2021 at 11:32 PM #182007
  Amin1233

  Hi . Anyone can help with coding a gap screener to find any stock that opens 2% lower than the lowest of last 10 days or 2% higher than the highest of the last 10 days and the open volume (Volume at the first minute bar) is above average of the past 10 days open volumes.

  

  Amin1233

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  11/23/2021 at 3:30 PM #182120
  robertogozzi

  There you go:

  N = 10 LL = lowest[N](low) HH = highest[N](high) c1 = open >= (HH[1] * 1.02) c2 = open <= (LL[1] * 0.98) c3 = volume > average[N](volume) SCREENER[(c1 OR c2) AND c3](volume as "Volume")

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  N  = 10 LL = lowest[N](low) HH = highest[N](high) c1 = open >= (HH[1] * 1.02) c2 = open <= (LL[1] * 0.98) c3 = volume > average[N](volume) SCREENER[(c1 OR c2) AND c3](volume as "Volume")

  The average volume is calculated on the whole bar itself, not just the first minute, as it’s not possible because there are only 254 bars available to scan backwards which is about 4 hours only!

   

   

  

  robertogozzi

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  11/27/2021 at 12:53 PM #182394
  robertogozzi

  The 254-bar limit scarcely allows to scan the first HOUR.
  This is with the first hour (you need to set the opening time of the FIRST hourly candle):

  Timeframe(Daily) LL = lowest[N](low) HH = highest[N](high) // Timeframe(1 hour) CheckTime = 000000 //time of the opening of the first hourly candle N = 10 t = 0 VL = 0 FOR i = 0 TO 254 IF OpenTime[i] = CheckTime THEN t = t + 1 VL = VL + volume[i] IF t = N THEN Break ENDIF ENDIF NEXT FirstHOUR = VL / t c1 = open >= (HH[1] * 1.02) c2 = open <= (LL[1] * 0.98) c3 = volume > FirstHOUR SCREENER[(c1 OR c2) AND c3](volume as "Volume")

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  Timeframe(Daily) LL = lowest[N](low) HH = highest[N](high) // Timeframe(1 hour) CheckTime = 000000     //time of the opening of the first hourly candle N  = 10 t  = 0 VL = 0 FOR i = 0 TO 254    IF OpenTime[i] = CheckTime THEN       t = t + 1       VL = VL + volume[i]       IF t = N THEN          Break       ENDIF    ENDIF NEXT FirstHOUR = VL / t c1 = open >= (HH[1] * 1.02) c2 = open <= (LL[1] * 0.98) c3 = volume > FirstHOUR SCREENER[(c1 OR c2) AND c3](volume as "Volume")

  As to the strategy I will be able to check the very first minute, as it allows to scan 200K bars!

  

  robertogozzi

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