indiquer la condition réalisée avec une flèche

• 03/21/2024 at 3:41 PM #230210
  kats

  Bonjour,

  je souhaite mettre une flèche m’indiquant que la réalisations de la condition est remplie mais uniquement sur le chandelier sur laquelle elle se réalise.

  Cependant la condition est une condition de close supérieur ou inferieur à une autre close sur un indicateur calculé ce qui fait que la flèche se positionne sur la bougie concernée mais également sur toutes les autres bougies qui suivent tant que la condition est vraie.

  Voilà le code que j’utilise:

  if c1 and c3 then
  DRAWARROWUP (barindex,low-slippage)coloured(255,255,0)

  endif
  if c2 and c4 then
  DRAWARROWDOWN (barindex,high+slippage)coloured(255,255,0)
  endif

  Ma question : est il possible de limiter cette indication sur la seule bougie ou la condition se réalise et si oui comment?

   

  Merci d’avance

   

  cdlt

  

  kats

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  03/21/2024 at 4:18 PM #230217
  JS

  Hi,

  You can try this:

  Limit Arrow Draw

  Once Up=0 Once Down=0 If C1 and C3 and Up=0 then DrawArrowUp(BarIndex,Low-Slippage)Coloured(0,255,0) Up=1 Down=0 EndIf If C2 and C4 and Down=0 then DrawArrowDown(BarIndex,High+Slippage)Coloured(255,0,0) Down=1 Up=0 EndIf

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  Once Up=0 Once Down=0   If C1 and C3 and Up=0 then DrawArrowUp(BarIndex,Low-Slippage)Coloured(0,255,0) Up=1 Down=0 EndIf   If C2 and C4 and Down=0 then DrawArrowDown(BarIndex,High+Slippage)Coloured(255,0,0) Down=1 Up=0 EndIf

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  kats

  

  JS

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  03/21/2024 at 4:20 PM #230218
  Iván

  Hi!
  You have to create a variable which change when conditions are met first time and this variable will change again when short conditions or exit conditions are met first time.

  // define your conditions c1 = close > close[1] c2 = high > high[1] longconditions = c1 and c2 sh1 = close < close[1] sh2 = low < low[1] shortconditions = sh1 and sh2 If longconditions and LngArrowOK = 0 THEN DRAWARROWUP(barindex, low-0.1*tr) coloured(0,255,0) LngArrowOK = 1 SrtArrowOK = 0 ELSif shortconditions and SrtArrowOK = 0 THEN DRAWARROWDOWN(barindex, high+0.1*tr) coloured(255,0,0) LngArrowOK = 0 SrtArrowOK = 1 ENDIF RETURN

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  // define your conditions c1 = close > close[1] c2 = high > high[1] longconditions = c1 and c2   sh1 = close < close[1] sh2 = low < low[1] shortconditions = sh1 and sh2   If longconditions and LngArrowOK = 0 THEN DRAWARROWUP(barindex, low-0.1*tr) coloured(0,255,0) LngArrowOK = 1 SrtArrowOK = 0 ELSif shortconditions and SrtArrowOK = 0 THEN DRAWARROWDOWN(barindex, high+0.1*tr) coloured(255,0,0) LngArrowOK = 0 SrtArrowOK = 1 ENDIF RETURN

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  kats

  

  Iván

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  03/21/2024 at 5:49 PM #230226
  kats

  Bonsoir

  tout d’abord merci pour ces réponses rapides.

  Par contre je n’ai pas compris le second message, est ce que je dois prendre le 1 ou le 2 pour répondre a ma demande svp

   

  Cdlt

  

  kats

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  03/21/2024 at 6:21 PM #230227
  JS

  Hi Kats,

  The answers have crossed each other but basically say the same thing…

  

  JS

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